The other day I made a grievous mistake over here. Not enough of a mistake to ruin everything, but enough to rain on my parade. Here we go again:
PROMPT:
Verify sqrt(HzsA^2)/A = A/A
Solve for Hz
PROMPT:
square Hz without simplifying from the quoted
Hz2\=s2⋅A4A4
PROMPT:
Account for the units contained in the quoted with Ohms, Newtons, meters
Prompt:
Show in terms of ohms, force, meters, simplified - Hz^2 = ((kg^2meters^4)/(s^6Ohm^2))/((kg^2meters^4)/(s^4Ohm^2))
This shows that the equation reduces to the standard form for frequency squared, and no additional terms from force or meters are needed in this context.
PROMPT:
From the previous, solve for Ω by not simplifying. Thanks.
PROMPT:
This allows us to express Ohm only in terms of Hz
PROMPT:
Use our framework to solve for seconds
PROMPT:
from our framework, I see A, Hz, and seconds in the following equation, therefore the previous relates with the equation sqrt(HzsA^2)A = A/A
PROMPT: This means all units can be expressed in terms of powers of Hz
PROMPT:
using our framework express Ω in terms of F visa-vi Hz REJECTING F = ma
PROMPT:
solve for meters - Hz^2 = ((kg^2meters^4)/(s^6Ohm^2))/((kg^2meters^4)/(s^4Ohm^2))
PROMPT:
using also s = cubedroot((kg*m^2)/A^2) express meters in terms of only seconds and seconds in terms of only meters
PROMPT:
multiply meters and seconds
PROMPT:
Does this establish a relationship between meters and seconds such that we can replace meters or replace seconds in our expression?
Prompt:
Combining Force and Ω, utilizing Hz, visa-vi units, we get:
F = (ΩC²)/ms
Where C = coulomb, m = meters, s = seconds
show the various forms that are unlocked by m*s in your last message
PROMPT:
this implies force can be expressed only in terms of meters of only in terms of seconds or only in terms of Hz
Each of these forms shows that
force can be expressed in terms of
meters,
seconds, or
Hz, depending on the context or the variables you want to work with. These relationships give you flexibility in how you approach problems involving
force, depending on which units you prefer to use.
PROMPT:
express Ω and C^2 in terms of Hz
Prompt:
From F = ΩC^2Hz^(5/2) plug in our new known values from the last message
PROMPT:
solve for acceleration in this context
PROMPT:
use this to express acceleration only in terms of Hz
Prompt:
solve for OHM as the only fundamental unit
PROMPT:
If C^2 = A^2/Hz^2 plug in A^2 = s^2/Hz^2
PROMPT:
this implies C can be expressed solely in terms of seconds (inverse of Hz), or Hz (inverse of s), and we also know the relationship between seconds and meters such that we can even express C in terms of only meters. Show how C can be expressed solely in terms of each of these three.
PROMPT:
express C in terms of only seconds
PROMPT:
We have meters in terms of seconds, we have seconds in terms of meters, we have C in terms of s, which implies we have C in terms of meters. And we know the relationship of Hz for each. Now use this relationship to solve for kg in terms of our framework. Reject f = ma in favor of:
Funified (expressed in Hz) = (ϕFn2^nPnΩ)/(r^2)
Funifiedmeters (expressed in Hz) = (ϕFn2^nPnΩ)/(r^2)(meters)
Pn = Prime n
Ω = Ohms
Hz = (ΩC²)/ms
Where C = coulomb, m = meters, s = seconds
or (Hzms)/C^2 = Ω
Or C = (Nms) / CΩ (expressed in units)
Which is normally begotten as C = ((Nms)/Ω)^(1/2)
Fm = (ΩC²)/s where m = meters
Hz = (ΩC²)/s
Where ΩC² = 1
-ΩC² = -1
e^iπ = -ΩC² (Euler’s) or -e^iπ = ΩC²
In place of all constants, choose PHI, squares, cubes, primes proportionality